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When the mass of a system is variable, a thrust force has to be applied on it in addition to all other forces acting on it. This thrust force is given by stack F with rightwards arrow on top equals stack v with rightwards arrow on top subscript r end subscript open parentheses plus-or-minus fraction numerator d m over denominator d t end fraction close parentheses Here stack v with rightwards arrow on top subscript r end subscriptis the relative velocity with which the mass dm either enters or leaves the system. A car has total mass 50 kg. Gases are ejected from this backwards with relative velocity 20 m/s. The rate of ejection of gas is 2 kg/s. Total mass of gas is 20 kg. Coefficient of friction between the car and road is mu = 0.1 Car will stop after (from starting) t = .... seconds :

  1. 12.2    
  2. 6.4    
  3. 10.6    
  4. 5.8    

The correct answer is: 5.8

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When the mass of a system is variable, a thrust force has to be applied on it in addition to all other forces acting on it. This thrust force is given by stack F with rightwards arrow on top equals stack v with rightwards arrow on top subscript r end subscript open parentheses plus-or-minus fraction numerator d m over denominator d t end fraction close parentheses Here stack v with rightwards arrow on top subscript r end subscriptis the relative velocity with which the mass dm either enters or leaves the system. A car has total mass 50 kg. Gases are ejected from this backwards with relative velocity 20 m/s. The rate of ejection of gas is 2 kg/total mass of gas is 20 kg. Coefficient of friction between the car and road is mu = 0.1 Maximum speed of car will be v = ..... m/s text (Take  end text l text  n  end text fraction numerator 4 over denominator 3 end fraction equals 0.28 text  ) end text

When the mass of a system is variable, a thrust force has to be applied on it in addition to all other forces acting on it. This thrust force is given by stack F with rightwards arrow on top equals stack v with rightwards arrow on top subscript r end subscript open parentheses plus-or-minus fraction numerator d m over denominator d t end fraction close parentheses Here stack v with rightwards arrow on top subscript r end subscriptis the relative velocity with which the mass dm either enters or leaves the system. A car has total mass 50 kg. Gases are ejected from this backwards with relative velocity 20 m/s. The rate of ejection of gas is 2 kg/total mass of gas is 20 kg. Coefficient of friction between the car and road is mu = 0.1 Maximum speed of car will be v = ..... m/s text (Take  end text l text  n  end text fraction numerator 4 over denominator 3 end fraction equals 0.28 text  ) end text

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When the mass of a system is variable, a thrust force has to be applied on it in addition to all other forces acting on it. This thrust force is given by stack F with rightwards arrow on top equals stack v with rightwards arrow on top subscript r end subscript open parentheses plus-or-minus fraction numerator d m over denominator d t end fraction close parentheses Here stack v with rightwards arrow on top subscript r end subscriptis the relative velocity with which the mass d m either enters or leaves the system. A car has total mass 50 kg. Gases are ejected from this backwards with relative velocity 20 m/s. The rate of ejection of gas is 2 kg/total mass of gas is 20 kg. Coefficient of friction between the car and road is mu = 0.1 Car will start moving after time t = . .. second:

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When two bodies collide normally, they exert equal and opposite impulses on each other. Impulse = change in linear momentum. Coefficient of restitution between two bodies is given by :– e equals fraction numerator text  IRelative velocity of separation  end text I over denominator text  IRelative velocity of approachl  end text end fraction equals 1 for elastic collision Two bodies collide as shown in figure. During collision they exert impulse of magnitude J on each other. For what values of J (in N–s) the 2 kg block will change its direction of velocity :

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When two bodies collide normally, they exert equal and opposite impulses on each other. Impulse = change in linear momentum. Coefficient of restitution between two bodies is given by :– e equals fraction numerator text  IRelative velocity of separation  end text I over denominator text  IRelative velocity of approachl  end text end fraction equals 1 for elastic collision Two bodies collide as shown in figure. During collision they exert impulse of magnitude J on each other. If the collision is elastic, the value of J is N–s :

When two bodies collide normally, they exert equal and opposite impulses on each other. Impulse = change in linear momentum. Coefficient of restitution between two bodies is given by :– e equals fraction numerator text  IRelative velocity of separation  end text I over denominator text  IRelative velocity of approachl  end text end fraction equals 1 for elastic collision Two bodies collide as shown in figure. During collision they exert impulse of magnitude J on each other. If the collision is elastic, the value of J is N–s :

physics-General
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A police car moving at22 blank m s to the power of negative 1 end exponent, changes a motorcyclist. The police man sounds his horn at 176 Hz, while both of them move towards a stationary siren of frequency 165 Hz. Calculate the speed of the motorcycle, if it is given that he does not observe any beats.

A police car moving at22 blank m s to the power of negative 1 end exponent, changes a motorcyclist. The police man sounds his horn at 176 Hz, while both of them move towards a stationary siren of frequency 165 Hz. Calculate the speed of the motorcycle, if it is given that he does not observe any beats.

physics-General
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Figure here shown an incident pulse P reflected from a rigid support. Which one of A comma B comma C comma D represents the reflected pulse correctly

Figure here shown an incident pulse P reflected from a rigid support. Which one of A comma B comma C comma D represents the reflected pulse correctly

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