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Complete step by step solution: Here we have the equation <img src="data:image/png;base64,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" class="Wirisformula" alt="square root of 4 x end root equals 11" width="74" height="19" style="vertical-align:-3px" role="math" data-mathml='«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«msqrt»«mn»4«/mn»«mi»x«/mi»«/msqrt»«mo»=«/mo»«mn»11«/mn»«/math»'/> <img src="data:image/png;base64,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" class="Wirisformula" alt="not stretchy rightwards double arrow left parenthesis 4 x right parenthesis to the power of 1 half end exponent equals 11" width="102" height="33" style="vertical-align:-2px" role="math" data-mathml='«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mo stretchy=¨false¨»§#8658;«/mo»«mo»(«/mo»«mn»4«/mn»«mi»x«/mi»«msup»«mo»)«/mo»«mfrac»«mn»1«/mn»«mn»2«/mn»«/mfrac»«/msup»«mo»=«/mo»«mn»11«/mn»«/math»'/> On squaring, we can write <img src="data:image/png;base64,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" class="Wirisformula" alt="left parenthesis square root of 4 x end root right parenthesis squared equals 11 squared" width="100" height="19" style="vertical-align:-3px" role="math" data-mathml='«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mo»(«/mo»«msqrt»«mn»4«/mn»«mi»x«/mi»«/msqrt»«msup»«mo»)«/mo»«mn»2«/mn»«/msup»«mo»=«/mo»«msup»«mn»11«/mn»«mn»2«/mn»«/msup»«/math»'/> ⇒ 4x = 121 ⇒ x = 30.25

Solve radical equation <img src="data:image/png;base64,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" class="Wirisformula" alt="square root of 4 x end root equals 11" width="74" height="19" style="vertical-align:-3px" role="math" data-mathml='«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«msqrt»«mn»4«/mn»«mi»x«/mi»«/msqrt»«mo»=«/mo»«mn»11«/mn»«/math»'/>

Solution for the question - solve radical equation sqrt(4x)=11

Solve radical equation sqrt(4x)=11  -Turito

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SOLUTION: HINT: Rearrange the equation and solve for x Complete step by step solution: Here we have the equation ∛x + 8 = 13 <img src="data:image/png;base64,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" class="Wirisformula" alt="not stretchy rightwards double arrow x to the power of 1 third end exponent plus 8 equals 13" width="109" height="32" style="vertical-align:-1px" role="math" data-mathml='«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mo stretchy=¨false¨»§#8658;«/mo»«msup»«mi»x«/mi»«mfrac»«mn»1«/mn»«mn»3«/mn»«/mfrac»«/msup»«mo»+«/mo»«mn»8«/mn»«mo»=«/mo»«mn»13«/mn»«/math»'/> On rearranging, we can write <img src="data:image/png;base64,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" class="Wirisformula" alt="x to the power of 1 third end exponent equals 13 minus 8 equals 5" width="116" height="32" style="vertical-align:-1px" role="math" data-mathml='«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«msup»«mi»x«/mi»«mfrac»«mn»1«/mn»«mn»3«/mn»«/mfrac»«/msup»«mo»=«/mo»«mn»13«/mn»«mo»§#8722;«/mo»«mn»8«/mn»«mo»=«/mo»«mn»5«/mn»«/math»'/> <img src="data:image/png;base64,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" class="Wirisformula" alt="not stretchy rightwards double arrow x to the power of 1 third end exponent equals 5" width="72" height="32" style="vertical-align:-1px" role="math" data-mathml='«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mo stretchy=¨false¨»§#8658;«/mo»«msup»«mi»x«/mi»«mfrac»«mn»1«/mn»«mn»3«/mn»«/mfrac»«/msup»«mo»=«/mo»«mn»5«/mn»«/math»'/> To make the power of the equation as 1, we have to raise the equation by 3 <img src="data:image/png;base64,iVBORw0KGgoAAAANSUhEUgAAAGUAAAAgCAYAAAAL6bYQAAAACXBIWXMAAA7EAAAOxAGVKw4bAAAABGJhU0UAAAAfTSyfawAAAdZJREFUeNpjYBh8QA2Ia4H4AsMoGDRgMRCnAfH/0aAYfGA0UkYjZRSMRspopIyC0UgZjZRRQK/IQMfUNvsXtB/kNhrcgwtoAPHD0WCgDaiGYkJi6IAJiN+NBh99IoaYCBEG4ilAnDgadMTXIfgwvojZTUSEwMyJHQ16+uQWYiIFBPiAuJUBMsY2CgZJ8QUDP0aDbnBV9LZAfGYQFNuDvnlOa4fCzAflkB1ALD/aPB/tRwz55vlI6UcMmeb5UO5HkNKcHzLN86HejyB1rG7INM+Hcj+C3AFUspvnJdAAIwYkA3EHFvFmqNxw7UeQEykUNc+roS0iayLVnwNicSR+IrSuoLlDaVw34Bvy+U+i+UQ1z4kdg2qFtpDwAQ8g7oOyXYB47xDtR5AamaB+1icg3gbERUDMQw+L50ItX0qEWtB4lD20Myg8gkYaWIDYmAGysPAGtN9F02z7H1pfMBFhXgE05egNo6YtqTOioJGJg7RyKKl1CkjdGmgRFskwsgHNGi0lJJSPSkC8CYi5oHrOjLDiCxnoAPHdgXaEKLSSQ44EHwbIOuHhDtYBsSW0aGeCNnZAERI0kI5igzpMGovccqgjhzMIBeJbQPyHATJ2twqITRlGwdAGAAOZrakLkaBhAAAA7HRFWHRNYXRoTUwAPG1hdGggeG1sbnM9Imh0dHA6Ly93d3cudzMub3JnLzE5OTgvTWF0aC9NYXRoTUwiPjxtbyBzdHJldGNoeT0iZmFsc2UiPiYjeDIxRDI7PC9tbz48bXN1cD48bWk+eDwvbWk+PG1yb3c+PG1mcmFjPjxtbj4xPC9tbj48bW4+MzwvbW4+PC9tZnJhYz48bW8+JiN4RDc7PC9tbz48bW4+MzwvbW4+PC9tcm93PjwvbXN1cD48bW8+PTwvbW8+PG1zdXA+PG1uPjU8L21uPjxtbj4zPC9tbj48L21zdXA+PC9tYXRoPoTJCjUAAAAASUVORK5CYII=" class="Wirisformula" alt="not stretchy rightwards double arrow x to the power of 1 third cross times 3 end exponent equals 5 cubed" width="101" height="32" style="vertical-align:-1px" role="math" data-mathml='«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mo stretchy=¨false¨»§#8658;«/mo»«msup»«mi»x«/mi»«mrow»«mfrac»«mn»1«/mn»«mn»3«/mn»«/mfrac»«mo»§#215;«/mo»«mn»3«/mn»«/mrow»«/msup»«mo»=«/mo»«msup»«mn»5«/mn»«mn»3«/mn»«/msup»«/math»'/> ⇒ x = 125

Solution for the question - solve radical equation x + 8 = 13

Solve radical equation x + 8 = 13-Turito

Hint:- An equation is said to be an identity if an only if, for all values of x (or any other variable in the equation), the equation will be true. i.e. for all values of x (or any other variable in the equation), LHS = RHS. Step-by-step solution:- LHS = t - 27 ............................................... (Equation i) RHS = - (27 - t) ∴ RHS = -(27) - (-t) ….................................... [Distributive property- a (m + n) = am + an] ∴ RHS = -27 + t ∴ RHS = t - 27 .............................................. (Equation ii) From Equation i &amp; ii, we get- LHS = RHS Hence, the given equation is not an identity. Final Answer:- ∴ The given equation is an identity and hence, it has infinitely many solutions. i.e. for any value of t, the equation will be satisfied i.e. LHS will be equal to RHS.

Solve each equation . is the equation an identity ? Explain . t-27 = - (27-t)

Solution for the question - solve each equation . is the equation an identity ? explain .t-27 = -(27-t)

Solve each equation . is the equation an identity ? explain .t--Turito

Hint:- An equation with variables on both sides of the "equal to" sign i.e. on LHS and RHS can be solved by first simplifying both the sides (Opening up the brackets, addition, subtraction, i.e. if any) and then all the variables are taken on 1 side of the equation and all the constants i.e. numbers on the other side. Both sides are then simplified further and the solution is obtained. Step-by-step solution:- <img src="data:image/png;base64,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" class="Wirisformula" alt="fraction numerator 2 x minus 2 over denominator 4 end fraction" width="56" height="35" style="vertical-align:-12px" role="math" data-mathml='«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mfrac»«mrow»«mn»2«/mn»«mi»x«/mi»«mo»-«/mo»«mn»2«/mn»«/mrow»«mn»4«/mn»«/mfrac»«/math»'/> +10 = x ∴ <img src="data:image/png;base64,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" class="Wirisformula" alt="fraction numerator 2 x minus 2 over denominator 4 end fraction" width="56" height="35" style="vertical-align:-12px" role="math" data-mathml='«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mfrac»«mrow»«mn»2«/mn»«mi»x«/mi»«mo»-«/mo»«mn»2«/mn»«/mrow»«mn»4«/mn»«/mfrac»«/math»'/> = x - 10 ........................ (Subtracting 10 both the sides) ∴ 2x - 2 = 4x - 40 ...................... (Multiplying both sides by 4) ∴ 2x - 4x = -40 + 2 ∴ -2x = -38 …....................... (Taking all variables and constants on either sides of the equation) ∴ x = -38/-2 ............................. (Dividing both sides by -2) ∴ x = 19 Final Answer:- ∴ Value of x for the given equation is 19.

Solve <img src="data:image/png;base64,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" class="Wirisformula" alt="fraction numerator 2 x minus 2 over denominator 4 end fraction" width="56" height="35" style="vertical-align:-12px" role="math" data-mathml='«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mfrac»«mrow»«mn»2«/mn»«mi»x«/mi»«mo»-«/mo»«mn»2«/mn»«/mrow»«mn»4«/mn»«/mfrac»«/math»'/> + 10= x

Solution for the question - solve (2x-2)/(4) + 10= x

Solve (2x-2)/(4) + 10= x -Turito

Hint:- An equation with variables on both sides of the "equal to" sign i.e. on LHS and RHS can be solved by first simplifying both the sides (Opening up the brackets, addition, subtraction, i.e. if any) and then all the variables are taken on 1 side of the equation and all the constants i.e. numbers on the other side. Both sides are then simplified further and the solution is obtained Step-by-step solution:- 6x - 5 = 2 (3x + 4) ∴ 6x - 5 = (2 × 3x) + (2 × 4) ..................... [Distributive property- a (m + n) = am + an] ∴ 6x - 5 = 6x + 8 ∴ 6x - 6x = 8 + 5 …....................... (Taking all variables and constants on either sides of the equation) ∴ 0 = 13 Since, after simplifying the given equation, the variable gets eliminated and LHS ≠ RHS, the given set of equations have no solution. i.e. for no value of x, the given equation will be satisfied. Final Answer:- ∴ The given system of equations have no solution.

What is the value of x in 6X-5 = 2 (3X+4)

Solution for the question - what is the value of x in 6x-5 = 2 (3x+4)

What is the value of x in 6x-5 = 2 (3x+4)-Turito

SOLUTION: HINT: write the reason Complete step by step solution: When there are two radical expressions in an equation, we isolate one radical expression then square both sides of the equation. Depending on whether there is a term added to the other radical expression, it will be expanded such that we isolate again and solve for the variable of the equation. The process is different from solving an equation with only one radical expression as there are more steps involved when there are two radical expressions.

Describe the process used to solve an equation with two radical expressions. How is this process different from solving an equation with only one radical expression

Solution for the question - describe the process used to solve an equation with two radicalexpressions. how is this process different from solving an equation w

Describe the process used to solve an equation with two radical-Turito

Hint:- An equation with variables on both sides of the "equal to" sign i.e. on LHS and RHS can be solved by first simplifying both the sides (Opening up the brackets, addition, subtraction, i.e. if any) and then all the variables are taken on 1 side of the equation and all the constants i.e. numbers on the other side. Both sides are then simplified further and the solution is obtained Step-by-step solution:- 4x + 6 = 2(2x + 3) ∴ 4x + 6 = (2 × 2x) + (2 × 3) ..................... [Distributive property- a (m + n) = am + an] ∴ 4x + 6 = 4x + 6 ∴ 4x - 4x = 6 - 6 …....................... (Taking all variables and constants on either sides of the equation) ∴ 0 = 0 Since, LHS = RHS the given set of equations are identical and hence, has infinitely many solutions. i.e. for any value of x, the given equation will be satisfied. Final Answer:- ∴ The given system of equations have infinitely many solutions.

Solution for the question - what is the value of x in 4x+6= 2(2x+3)

What is the value of x in 4x+6= 2(2x+3)-Turito

Hint:- An equation with variables on both sides of the "equal to" sign i.e. on LHS and RHS can be solved by first simplifying both the sides (Opening up the brackets, addition, subtraction, i.e. if any) and then all the variables are taken on 1 side of the equation and all the constants i.e. numbers on the other side. Both sides are then simplified further and the solution is obtained. Step-by-step solution:- <img src="data:image/png;base64,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" class="Wirisformula" alt="fraction numerator 6 x plus 8 over denominator 2 end fraction" width="56" height="35" style="vertical-align:-12px" role="math" data-mathml='«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mfrac»«mrow»«mn»6«/mn»«mi»x«/mi»«mo»+«/mo»«mn»8«/mn»«/mrow»«mn»2«/mn»«/mfrac»«/math»'/> - 4 = 3x ∴ <img src="data:image/png;base64,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" class="Wirisformula" alt="fraction numerator 6 x plus 8 over denominator 2 end fraction" width="56" height="35" style="vertical-align:-12px" role="math" data-mathml='«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mfrac»«mrow»«mn»6«/mn»«mi»x«/mi»«mo»+«/mo»«mn»8«/mn»«/mrow»«mn»2«/mn»«/mfrac»«/math»'/> = 3x + 4 ........................ (Adding 4 both the sides) ∴ 6x + 8 = 6x + 8 ...................... (Multiplying both sides by 2) ∴ 6x - 6x = 8 - 8 ∴ 0 = 0 Since, LHS = RHS the given set of equations are identical and hence, has infinitely many solutions. i.e. for any value of x, the given equation will be satisfied. Final Answer:- ∴ The given system of equations have infinitely many solutions.

Solve  <img src="data:image/png;base64,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" class="Wirisformula" alt="fraction numerator 6 x plus 8 over denominator 2 end fraction" width="56" height="35" style="vertical-align:-12px" role="math" data-mathml='«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mfrac»«mrow»«mn»6«/mn»«mi»x«/mi»«mo»+«/mo»«mn»8«/mn»«/mrow»«mn»2«/mn»«/mfrac»«/math»'/> - 4 = 3x

Solution for the question - solve (6x+8)/(2) -4= 3x

Solve (6x+8)/(2) -4= 3x -Turito

Hint:- An equation with variables on both sides of the "equal to" sign i.e. on LHS and RHS can be solved by first simplifying both the sides (Opening up the brackets, addition, subtraction, i.e. if any) and then all the variables are taken on 1 side of the equation and all the constants i.e. numbers on the other side. Both sides are then simplified further and the solution is obtained Step-by-step solution:- 5/8(16d + 24) = 6(d - 1) + 1 ∴ (5/8 × 16d) + (5/8 × 24) = 6d - 6 + 1 ..................... [Distributive property- a (m+n) = am + an] ∴ 10d + 15 = 6d - 5 ∴ 10d - 6d = -5 - 15 …....................... (Taking all variables and constants on either sides of the equation) ∴ 4d = -20 ∴ d = -20/4 ............................................. (Dividing both sides by 4) ∴ d = -5 Final Answer:- ∴ Value of d for the given equation is -5.

Solution for the question - 5/8(16d+24) = 6 (d-1)+1

5/8(16d+24) = 6 (d-1)+1-Turito

Hint:- An equation with variables on both sides of the "equal to" sign i.e. on LHS and RHS can be solved by first simplifying both the sides (Opening up the brackets, addition, subtraction, i.e. if any) and then all the variables are taken on 1 side of the equation and all the constants i.e. numbers on the other side. Both sides are then simplified further and the solution is obtained. Step-by-step solution:- (-3k + 4) = -2 - 6k ∴ -3k + 4 = -2 - 6k ∴ -3k + 6k = -2 - 4 …....................... (Taking all variables and constants on either sides of the equation) ∴ 3k = -6 ∴ k = <img src="data:image/png;base64,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" class="Wirisformula" alt="fraction numerator negative 6 over denominator 3 end fraction" width="31" height="35" style="vertical-align:-12px" role="math" data-mathml='«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mfrac»«mrow»«mo»-«/mo»«mn»6«/mn»«/mrow»«mn»3«/mn»«/mfrac»«/math»'/> ............................ (Dividing both sides by 3) ∴ k = -2 Final Answer:- ∴ Value of k for the given equation is -2.

Solution for the question - solve (-3k + 4)= -2 - 6k

Solve (-3k + 4)= -2 - 6k-Turito

Hint:- An equation with variables on both sides of the "equal to" sign i.e. on LHS and RHS can be solved by first simplifying both the sides (Opening up the brackets, addition, subtraction, i.e. if any) and then all the variables are taken on 1 side of the equation and all the constants i.e. numbers on the other side. Both sides are then simplified further and the solution is obtained Step-by-step solution:- 100(Z - 0.2) = -10(5Z + 0.8) ∴ 100 × z - 100 × 0.2 = (-10 × 5z) -(10 × 0.8) .................................... [Distributive property- a (m + n) = am + an] ∴ 100z - 20 = -50z - 8 ∴ 100z + 50z = -8 + 20 …................................. (Taking all variables and constants on either sides of the equation) ∴ 150z = 12 ∴ z = 12/150 ............................................. (Dividing both sides by 150) ∴ z = 0.08 Final Answer:- ∴ Value of z for the given equation is 0.08.

Solution for the question - solve : 100 (z-0.2) = -10( 5z+0.8)

Solve : 100 (z-0.2) = -10( 5z+0.8)-Turito

Hint:- An equation with variables on both sides of the "equal to" sign i.e. on LHS and RHS can be solved by first simplifying both the sides (Opening up the brackets, addition, subtraction, i.e. if any) and then all the variables are taken on 1 side of the equation and all the constants i.e. numbers on the other side. Both sides are then simplified further and the solution is obtained Step-by-step solution:- <img src="data:image/png;base64,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" class="Wirisformula" alt="fraction numerator q plus 1 over denominator 2 end fraction equals fraction numerator q minus 1 over denominator 3 end fraction" width="109" height="35" style="vertical-align:-12px" role="math" data-mathml='«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mfrac»«mrow»«mi»q«/mi»«mo»+«/mo»«mn»1«/mn»«/mrow»«mn»2«/mn»«/mfrac»«mo»=«/mo»«mfrac»«mrow»«mi»q«/mi»«mo»-«/mo»«mn»1«/mn»«/mrow»«mn»3«/mn»«/mfrac»«/math»'/> ∴ 3 × (q + 1) = 2 × (q - 1) ................................. (Cross-multiplying) ∴ (3 × q) + (3 × 1) = (2 × q) - (2 × 1) ..................... [Distributive property- a (m+n) = am + an] ∴ 3q + 3 = 2q - 2 ∴ 3q - 2q = -2 - 3 …....................... (Taking all variables and constants on either sides of the equation) ∴ q = -5 Final Answer:- ∴ Value of q for the given equation is -5.

Solution for the question - (q+1)/(2)=(q-1)/(3)

(q+1)/(2)=(q-1)/(3)  -Turito

Hint:- An equation with variables on both sides of the "equal to" sign i.e. on LHS and RHS can be solved by first simplifying both the sides (Opening up the brackets, addition, subtraction, i.e. if any) and then all the variables are taken on 1 side of the equation and all the constants i.e. numbers on the other side. Both sides are then simplified further and the solution is obtained Step-by-step solution:- (n - 4)/2 - 7 = -2n+6 ∴ (n - 4)/2 = -2n + 6 + 7 .................................... (Taking all constants on RHS) ∴ n - 4 = -4n + 12 + 14 ................................ (Multiplying both sides by 2) ∴ n + 4n = 12 + 14 + 4 …................................. (Taking all variables and constants on either sides of the equation) ∴ 5n = 30 ∴ n = 30/5 ............................................. (Dividing both sides by 5) ∴ n = 6 Final Answer:- ∴ Value of n for the given equation is 6.

Find the value of n in the equation shown : (n-4)/2 - 7 = -2n+6

Solution for the question - find the value of n in the equation shown :(n-4)/2 - 7 = -2n+6

Find the value of n in the equation shown :(n-4)/2 - 7 = -2n+6-Turito

Hint:- An equation with variables on both sides of the "equal to" sign i.e. on LHS and RHS can be solved by first simplifying both the sides (Opening up the brackets, addition, subtraction, i.e. if any) and then all the variables are taken on 1 side of the equation and all the constants i.e. numbers on the other side. Both sides are then simplified further and the solution is obtained Step-by-step solution:- 3x - 10 + 4x = -2(x - 4) + 9 ∴ 3x - 10 + 4x = (-2 × x) [-2 × (-4)] + 9 …................. [Distributive property- a (m+n) = am + an] ∴ 3x - 10 + 4x = -2x + 8 + 9 ∴ 3x + 4x + 2x = 8 + 9 + 10 ….................................. (Taking all variables and constants on either sides of the equation) ∴ 9x = 27 ∴ x = 27/9 ............................................. (Dividing both sides by 9) ∴ x = 3 Final Answer:- ∴ Value of x for the given equation is 3.

What is the value of X in the equation shown : 3x-10+4x= -2(x-4)+9

Solution for the question - what is the value of x in the equation shown :3x-10+4x= -2(x-4)+9

What is the value of x in the equation shown :3x-10+4x= -2(x-4)-Turito

Hint:- An equation with variables on both sides of the "equal to" sign i.e. on LHS and RHS can be solved by first simplifying both the sides (Opening up the brackets, addition, subtraction, i.e. if any) and then all the variables are taken on 1 side of the equation and all the constants i.e. numbers on the other side. Both sides are then simplified further and the solution is obtained. Step-by-step solution:- 16(4 - 3m) = 96(<img src="data:image/png;base64,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" class="Wirisformula" alt="fraction numerator negative m over denominator 2 end fraction" width="37" height="32" style="vertical-align:-12px" role="math" data-mathml='«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mfrac»«mrow»«mo»-«/mo»«mi»m«/mi»«/mrow»«mn»2«/mn»«/mfrac»«/math»'/> + 1) ∴ (16 × 4) - (16 × 3m) = (96 × <img src="data:image/png;base64,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" class="Wirisformula" alt="fraction numerator negative m over denominator 2 end fraction" width="37" height="32" style="vertical-align:-12px" role="math" data-mathml='«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mfrac»«mrow»«mo»-«/mo»«mi»m«/mi»«/mrow»«mn»2«/mn»«/mfrac»«/math»'/>) + (96 × 1) ..................... [Distributive property- a (m+n) = am + an] ∴ 64 - 48m = -48m + 96 ∴ -48m + 48m = 96 - 64 …....................... (Taking all variables and constants on either sides of the equation) ∴ 0 = 32 Since, after simplifying the given equation, the variable gets eliminated and LHS ≠ RHS, the given set of equations have no solution. i.e. for no value of m, the given equation will be satisfied. Final Answer:- ∴ The given system of equations have no solution.

Solve 16(4 - 3m) = 96(<img src="data:image/png;base64,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" class="Wirisformula" alt="fraction numerator negative m over denominator 2 end fraction
" width="37" height="32" style="vertical-align:-6px" role="math" data-mathml='«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mfrac»«mrow»«mo»-«/mo»«mi»m«/mi»«/mrow»«mn»2«/mn»«/mfrac»«mspace linebreak=¨newline¨/»«/math»'/>  + 1)

Hint:- An equation with variables on both sides of the "equal to" sign i.e. on LHS and RHS can be solved by first simplifying both the sides (Opening up the brackets, addition, subtraction, i.e. if any) and then all the variables are taken on 1 side of the equation and all the constants i.e. numbers on the other side. Both sides are then simplified further and the solution is obtained. Step-by-step solution:- <img src="data:image/png;base64,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" class="Wirisformula" alt="fraction numerator 4 x plus 6 over denominator 2 end fraction equals fraction numerator 3 x minus 15 over denominator 3 end fraction" width="139" height="35" style="vertical-align:-12px" role="math" data-mathml='«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mfrac»«mrow»«mn»4«/mn»«mi»x«/mi»«mo»+«/mo»«mn»6«/mn»«/mrow»«mn»2«/mn»«/mfrac»«mo»=«/mo»«mfrac»«mrow»«mn»3«/mn»«mi»x«/mi»«mo»-«/mo»«mn»15«/mn»«/mrow»«mn»3«/mn»«/mfrac»«/math»'/> ∴ 3 × (4x + 6) = 2 × (3x - 15) ................................. (Cross-multiplying) ∴ (3 × 4x) + (3 × 6) = (2 × 3x) - (2 × 15) ..................... [Distributive property- a (m+n) = am + an] ∴ 12x + 18 = 6x - 30 ∴ 12x - 6x = -30 - 18 …....................... (Taking all variables and constants on either sides of the equation) ∴ 6x = -48 ∴ x = <img src="data:image/png;base64,iVBORw0KGgoAAAANSUhEUgAAACkAAAAjCAYAAAAJ+yOQAAAACXBIWXMAAA7EAAAOxAGVKw4bAAAABGJhU0UAAAAXQ/cXWQAAAY1JREFUeNrtmDFLw0AYho8gHUTcHMTBRUQcpCAiIkUKTuIggog4FkRE/BeCg5ObiKOLg4ODuIiIOAjFwaFIwUnEXYocRajvR94hhEsMYpJvuBceyLVwefjuLsmdMfllGfQS/usHR6ADLLgGI6bgDIBWiuQp2Ad9oAIOwGPRksegkSJpY+0AdIsUnAc3vE6S7LDaUcm3ogRl6J7B6C+SMh/3Iu05cFiUpMyt3Ug7SXKKwyvcgQ9Q+8sNexmI3/jB0Uc8UuUzMMzKS6bBK/vINbI6xzJIXiTI1MFt3pJZq25T+rCmhLgq2XJUXDLJualCcpWidT56Al7LnNzWIilZA09c3ZYrfMX4+PiU8zAuAx8fHy2ZAefgk+/kS7CgSXCLUuNsD4JNcK9FUL4Fm9qHWfbZG9olX7ixUh3LuSibrC9+zDY5J1W99+VLe8mE5zsBTzLaYEeLpDxyXKdiVfCuRfKK1XOlq0VShnTd8fuEKeFILykV7vganJOSWRMeXi1qWjxD4MSEx3rflK79R8c/3XqDVqYbagcAAAB6dEVYdE1hdGhNTAA8bWF0aCB4bWxucz0iaHR0cDovL3d3dy53My5vcmcvMTk5OC9NYXRoL01hdGhNTCI+PG1mcmFjPjxtcm93Pjxtbz4tPC9tbz48bW4+NDg8L21uPjwvbXJvdz48bW4+NjwvbW4+PC9tZnJhYz48L21hdGg+ILTaZwAAAABJRU5ErkJggg==" class="Wirisformula" alt="fraction numerator negative 48 over denominator 6 end fraction" width="41" height="35" style="vertical-align:-12px" role="math" data-mathml='«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mfrac»«mrow»«mo»-«/mo»«mn»48«/mn»«/mrow»«mn»6«/mn»«/mfrac»«/math»'/> ............................................. (Dividing both sides by 6) ∴ x = -8 Final Answer:- ∴ Value of x for the given equation is -8.

Solution for the question - (4x+6)/(2)=(3x-15)/(3)

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Solve radical equation

Rearrange the equation and solve for x

The correct answer is: x = 30.25

Complete step by step solution:Here we have the equation On squaring, we can write ⇒ 4x = 121⇒ x = 30.25

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