Maths-
General
Easy

Question

Find the area of the trapezium ABCD with the given values.

hintHint:

Draw the parallel line from B parallel to AD which cuts the CD at E .
We get a triangle and parallelogram. we find the area of triangle in both heron's
method and using formula area = ½ b × h and equating we get height h
Now , find the area of Trapezium =  ½ height × (sum of lengths of parallel sides).

The correct answer is: 6576 cm2


    Ans :- 6,576 cm2.
    Explanation :-
    Step 1:- Given lengths of parallel sides is 120 and 154 cm .
    Length of non parallel sides is 50 and 52 cm
    We get a triangle and parallelogram ABED
    we get BE = 50 cm ; DE = 120 cm (opposites sides of parallelogram )
    CE = CD-DE = 154 - 120 = 34 cm .

    Step 2:- Equate the areas and find value of height h
    17 cross times space h equals 816 not stretchy rightwards double arrow h equals 816 over 17 equals 48 cm
    Step 3:-Find the area of trapezium
    text  Area of trapezium  end text equals 1 half cross times left parenthesis text  height  end text right parenthesis cross times left parenthesis text  sumoflengthsofparallelsides  end text right parenthesis
    text  Area of trapezium  end text equals 1 half cross times left parenthesis 48 right parenthesis cross times left parenthesis 120 plus 154 right parenthesis equals 24 cross times 274 equals 6576 cm squared
    Therefore, Area of trapezium ABCD  = 6,576 cm2.

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