X + 2Y = 4
2X - 5Y = - 1

The correct answer is: We can also solve these system of equations by making the coefficients of y to be the same in both the equations.

Complete step by step solution:
Let x + 2y = 4…(i)
and 2x - 5y = - 1…(ii)
On multiplying (i) with 2, we get 2(x + 2y = 4)
⇒ 2x + 4y = 8…(iii)
Now, we have the coefficients of x in (ii) and (iii) to be the same.
On subtracting (ii) from (iii),
we get LHS to be 2x + 4y - (2x - 5y) = 4y + 5y = 9y
and RHS to be 8 - (- 1) = 9
On equating LHS and RHS, we have 9y = 9
⇒ y = 1
On substituting the value of  in (i), we get x + 2×1 = 4
⇒ x + 2 = 4
⇒ x = 2
Hence we get  and
Note: We can also solve these system of equations by making the coefficients of y
to be the same in both the equations.