Question
Energy levels A, B, C of a certain atom corresponds to increasing values of energy i.e. EA < EB < EC. If , and are the wavelengths of radiations corresponding to the transitions C to B, B to A and C to A respectively, which of the following statement is correct.
The correct answer is:
Related Questions to study
The ionization constant of in water is 5.6 ×´ 10-10 at 25oC. The rate constant for the reaction of and OH- to form NH3 and H2O at 25oC is 3.4 × 1010 L mol-1 s-1. The rate constant for proton transfer from water to NH3 is
The ionization constant of in water is 5.6 ×´ 10-10 at 25oC. The rate constant for the reaction of and OH- to form NH3 and H2O at 25oC is 3.4 × 1010 L mol-1 s-1. The rate constant for proton transfer from water to NH3 is
For the curve y2 = (x + a)3 the square of the sub tangent varies as
For such questions, we should know the concept of subnormal and subtangent.
For the curve y2 = (x + a)3 the square of the sub tangent varies as
For such questions, we should know the concept of subnormal and subtangent.
The length of the subtangent at any point on y = f(x) is 3/8 and the length of the subnormal is 24 then the ordinate of the point is
For such questions, we should know the formula to find subtangent and subnormal.
The length of the subtangent at any point on y = f(x) is 3/8 and the length of the subnormal is 24 then the ordinate of the point is
For such questions, we should know the formula to find subtangent and subnormal.
The length of the portion of the tangent at any point on the curve x2/3 + y2/3 = a2/3 intercepted between the axis is
The length of the portion of the tangent at any point on the curve x2/3 + y2/3 = a2/3 intercepted between the axis is
The equation of the tangent to the curve x2 + 2y = 8 which is the perpendicular to x – 2y + 1 = 0 is
For such questions, we should know the formula to find the tangent and slope of lines and curves.
The equation of the tangent to the curve x2 + 2y = 8 which is the perpendicular to x – 2y + 1 = 0 is
For such questions, we should know the formula to find the tangent and slope of lines and curves.
In an isosceles triangle the ends of the base are (2a, 0) and (0, a) and one side is parallel to x – axis. The third vertex is
In an isosceles triangle the ends of the base are (2a, 0) and (0, a) and one side is parallel to x – axis. The third vertex is
If x + 2y + 3 = 0, x + 2y – 7 = 0 and 2x – y – 4 = 0 form the sides of square, the equation of the fourth side is
For such questions, we should know properties of square. We should know the formula to find distance between two parallel lines.
If x + 2y + 3 = 0, x + 2y – 7 = 0 and 2x – y – 4 = 0 form the sides of square, the equation of the fourth side is
For such questions, we should know properties of square. We should know the formula to find distance between two parallel lines.
The number of real values of k for which the lines x – 2y + 3 = 0, kx + 3y + 1 = 0 and 4x – ky + 2 = 0 are concurrent is
For such questions, we should know properties of concurrent lines.
The number of real values of k for which the lines x – 2y + 3 = 0, kx + 3y + 1 = 0 and 4x – ky + 2 = 0 are concurrent is
For such questions, we should know properties of concurrent lines.
The distance of the line 2x – 3y = 4 from the point (1, 1) in the direction of the line x + y = 1 is
The distance of the line 2x – 3y = 4 from the point (1, 1) in the direction of the line x + y = 1 is
The mid points of the sides of a triangle are (5, 0), (5, 12) and (0, 12). The orthocentre of this triangle is
The mid points of the sides of a triangle are (5, 0), (5, 12) and (0, 12). The orthocentre of this triangle is
The image of the point A (1, 2) by the line mirror y = x is the point B and the image of B by line mirror y = 0 is the point
The image of the point A (1, 2) by the line mirror y = x is the point B and the image of B by line mirror y = 0 is the point
If
For such questions, we should know different trigonometric formulas. We should simplify the function first before finding derivatives.
If
For such questions, we should know different trigonometric formulas. We should simplify the function first before finding derivatives.