Maths-
General
Easy

Question

The resultant of two forces 3P and 2P is R, if the first force is doubled, the resultant is also doubled. The angle between the forces is

  1. fraction numerator pi over denominator 3 end fraction    
  2. fraction numerator 2 pi over denominator 3 end fraction    
  3. fraction numerator pi over denominator 6 end fraction    
  4. fraction numerator 5 pi over denominator 6 end fraction    

hintHint:

In this question, the resultant of two forces 3P and 2P is R, if the first force is doubled, the resultant is also doubled. We have to find the angle between the force.  We have formula for resultant that is square root of left parenthesis a squared plus b squared plus 2 a b cos theta end root right parenthesis. Use this formula to find the answer

The correct answer is: fraction numerator 2 pi over denominator 3 end fraction


    ......(i)
    and .....(ii)
    So multiplying (i) by 2 and squaring and subtracting (ii) from (i), we get

    Þ Þ .
    Here we have to find the Angle between the forces,
    Firstly, we have given resultant R has two forces 3P and 2P.
    We have resultant formula,
    R = square root of left parenthesis a squared plus b squared plus 2 a b space c o s theta right parenthesis end root
    R = square root of left parenthesis 3 P squared plus 2 P squared plus 2 x 3 P x 2 P space x space c o s theta right parenthesis end root
    Squaring both sided,
    left parenthesis 3 P squared plus 2 P squared plus 2 x 3 P x 2 P space x space c o s theta right parenthesis
    R squared equals 13 P squared plus 12 P squared c o s theta --------(1)
    first force is doubled, the resultant is also doubled. Then at 2R → 2x 3p
    2 R equals square root of left parenthesis 6 P squared plus 2 P squared plus 2 space x space 6 P space x space 2 p space x space cos theta right parenthesis end root
    Squaring both sides,
    4 R squared equals 36 P squared plus 4 P squared plus 24 P squared c o s theta
    4 R squared equals 40 P squared plus 24 P squared c o s theta -------(2)
    Now, multiplying eq (1) by 4 we get,
    4 R squared equals 52 P squared plus 48 P squared c o s theta --------(3)
    Now equating eq (2) and eq (3), we get,
    40 P squared plus 24 P squared c o s theta equals 52 P squared plus 48 P squared c o s theta
    12 P squared equals negative 24 P squared c o s theta
    C o s theta space equals space minus 1 half
    θ = 120°
    Therefore, the angle between the forces is 120°
    The correct answer is 120°.

    In this question, we have to make two equations of Resultant as per given instruction and solve the equations and find the angle. Remember the formula of Resultant is R = square root of left parenthesis a squared plus b squared plus 2 a b space cos theta right parenthesis end root.

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