Chemistry-
General
Easy

Question

In which of the following molecules are all the bonds not equal?

  1. AlF3    
  2. NF3    
  3. ClF3    
  4. BF3    

The correct answer is: ClF3

Related Questions to study

General
chemistry-

The formal charge of the O-atoms in the ion is:

The formal charge of the O-atoms in the ion is:

chemistry-General
General
Maths-

The incentre of the triangle formed by the links x=0, y=0 and 3x+4y=12 is at

In order to answer this question, we used the formula for the coordinates of a triangle's in-center when the lengths of its sides a, b, and c are known, as well as the coordinates of its vertices. The incentre is (1,1).

The incentre of the triangle formed by the links x=0, y=0 and 3x+4y=12 is at

Maths-General

In order to answer this question, we used the formula for the coordinates of a triangle's in-center when the lengths of its sides a, b, and c are known, as well as the coordinates of its vertices. The incentre is (1,1).

General
Maths-

Two vertices of a triangle are (3,-2) and (-2,3) and its orthocentre is (-6,1). Then its third vertex is

 2x+y-4=0 and the x-y+7=0 are the equations that pass through the third vertex.

Two vertices of a triangle are (3,-2) and (-2,3) and its orthocentre is (-6,1). Then its third vertex is

Maths-General

 2x+y-4=0 and the x-y+7=0 are the equations that pass through the third vertex.

parallel
General
Maths-

If in triangle ABC comma straight A identical to left parenthesis 1 comma 10 right parenthesis, circumcenter identical to open parentheses negative 1 third comma 2 over 3 close parentheses and orthocenter identical to open parentheses 11 over 3 comma 4 over 3 close parentheses then the co-ordinates of mid-point of side opposite to  is :

>>> The orthocenter, centroid and circumcenter of any triangle are collinear. And the centroid divides the distance from orthocenter to circumcenter in the ratio 2:1.
>>> Also, the centroid (G) divides the medians (AD) in the ratio 2:1. 
>>> D(hk)=(1,negative 11 over 3)

If in triangle ABC comma straight A identical to left parenthesis 1 comma 10 right parenthesis, circumcenter identical to open parentheses negative 1 third comma 2 over 3 close parentheses and orthocenter identical to open parentheses 11 over 3 comma 4 over 3 close parentheses then the co-ordinates of mid-point of side opposite to  is :

Maths-General

>>> The orthocenter, centroid and circumcenter of any triangle are collinear. And the centroid divides the distance from orthocenter to circumcenter in the ratio 2:1.
>>> Also, the centroid (G) divides the medians (AD) in the ratio 2:1. 
>>> D(hk)=(1,negative 11 over 3)

General
maths-

A triangle ABC with vertices A(-1,0), B(-2,3/4)&C(-3,-7/6) has its orthocentre H. Then the orthocentre of triangle BCH will be

A triangle ABC with vertices A(-1,0), B(-2,3/4)&C(-3,-7/6) has its orthocentre H. Then the orthocentre of triangle BCH will be

maths-General
General
Maths-

ABC is an equilateral triangle such that the vertices B and C lie on two parallel lines at a distance 6 If A lies between the parallel lines at a distance 4 from one of them then the length of a side of the equilateral triangle is

 >>> acosθ=6 ----(1)
 >>> a(sin(30θ))=4 ----(2)
>>> a = fraction numerator 4 square root of 7 over denominator square root of 3 end fraction

ABC is an equilateral triangle such that the vertices B and C lie on two parallel lines at a distance 6 If A lies between the parallel lines at a distance 4 from one of them then the length of a side of the equilateral triangle is

Maths-General

 >>> acosθ=6 ----(1)
 >>> a(sin(30θ))=4 ----(2)
>>> a = fraction numerator 4 square root of 7 over denominator square root of 3 end fraction

parallel
General
Maths-

If the point left parenthesis 1 plus cos invisible function application theta comma sin invisible function application theta right parenthesis lies between the region corresponding to the acute angle between the lines x-3y=0 and x-6y=0 then

>>> L11 cross times L22 <0
>>>   (1+costheta)2 -6sintheta -6sinthetacostheta -3sintheta-3sinthetacostheta+18sintheta2 < 0

If the point left parenthesis 1 plus cos invisible function application theta comma sin invisible function application theta right parenthesis lies between the region corresponding to the acute angle between the lines x-3y=0 and x-6y=0 then

Maths-General

>>> L11 cross times L22 <0
>>>   (1+costheta)2 -6sintheta -6sinthetacostheta -3sintheta-3sinthetacostheta+18sintheta2 < 0

General
Maths-

If P open parentheses 1 plus fraction numerator alpha over denominator square root of 2 end fraction comma 2 plus fraction numerator alpha over denominator square root of 2 end fraction close parentheses be any point on a line then the range of  for which the point ' P ' lies between the parallel lines x+2y=1 and 2x+4y=15 is

((1+fraction numerator alpha over denominator square root of 2 end fraction)+2(2 plus fraction numerator alpha over denominator square root of 2 end fraction) -1).(2 left parenthesis 1 plus fraction numerator alpha over denominator square root of 2 end fraction right parenthesis plus 4 left parenthesis 2 plus fraction numerator alpha over denominator square root of 2 end fraction right parenthesis minus 15) < 0

If P open parentheses 1 plus fraction numerator alpha over denominator square root of 2 end fraction comma 2 plus fraction numerator alpha over denominator square root of 2 end fraction close parentheses be any point on a line then the range of  for which the point ' P ' lies between the parallel lines x+2y=1 and 2x+4y=15 is

Maths-General

((1+fraction numerator alpha over denominator square root of 2 end fraction)+2(2 plus fraction numerator alpha over denominator square root of 2 end fraction) -1).(2 left parenthesis 1 plus fraction numerator alpha over denominator square root of 2 end fraction right parenthesis plus 4 left parenthesis 2 plus fraction numerator alpha over denominator square root of 2 end fraction right parenthesis minus 15) < 0

General
maths-

is any point in the interior of the quadrilateral formed by the pair of lines  and the two lines 2x+y-2=0 and 4x+5y=20 then the possible number of positions of the points ' P ' is

is any point in the interior of the quadrilateral formed by the pair of lines  and the two lines 2x+y-2=0 and 4x+5y=20 then the possible number of positions of the points ' P ' is

maths-General
parallel
General
Maths-

If the point P open parentheses a squared comma a close parentheses subscript minus,lies in the region corresponding to the acute angle between the lines 2y=x and 4y=x then - .....

u ≡ x - 2y = 0 and v ≡ x - 4y = 0
>>>    S(x, y) ≡ x² - 6xy + 8y² = 0
>>>     ( a - 2 )( a - 4 ) < 0

If the point P open parentheses a squared comma a close parentheses subscript minus,lies in the region corresponding to the acute angle between the lines 2y=x and 4y=x then - .....

Maths-General

u ≡ x - 2y = 0 and v ≡ x - 4y = 0
>>>    S(x, y) ≡ x² - 6xy + 8y² = 0
>>>     ( a - 2 )( a - 4 ) < 0

General
Maths-

Consider A(0,1) and B(2,0) and P be a point on the line 4x+3y+9=0, co-ordinates of P such vertical line PA minus PB vertical line is maximum is

 Hence the point is (negative 18 over 59 over 5).

Consider A(0,1) and B(2,0) and P be a point on the line 4x+3y+9=0, co-ordinates of P such vertical line PA minus PB vertical line is maximum is

Maths-General

 Hence the point is (negative 18 over 59 over 5).

General
Maths-

Assertion (A): The lines represented by 3 x squared plus 10 x y plus 3 y squared minus 16 x minus 16 y plus 16 equals 0 and x+ y=2 do not form a triangle
Reason (R): The above three lines concur at (1,1)

Both Assertion and Reason are correct and the Reason is the correct explanation of Assertion.

Assertion (A): The lines represented by 3 x squared plus 10 x y plus 3 y squared minus 16 x minus 16 y plus 16 equals 0 and x+ y=2 do not form a triangle
Reason (R): The above three lines concur at (1,1)

Maths-General

Both Assertion and Reason are correct and the Reason is the correct explanation of Assertion.

parallel
General
chemistry-

In Bohr’s hydrogen atom, the electronic transition emitting light of longest wavelength is:

In Bohr’s hydrogen atom, the electronic transition emitting light of longest wavelength is:

chemistry-General
General
Maths-

P1,P2,P3, be the product of perpendiculars from (0,0) to  x y plus x plus y plus 1 equals 0 comma x squared minus y squared plus 2 x plus 1 equals 0 comma 2 x squared plus 3 x y minus 2 y squared plus 3 x plus y plus 1 equals 0  respectively then:

P1 = 1;
P2 = 1 half;
P3 = fraction numerator 1 over denominator square root of 7 end fraction;
>>> Therefore, we can say that P1>P2>P3.

P1,P2,P3, be the product of perpendiculars from (0,0) to  x y plus x plus y plus 1 equals 0 comma x squared minus y squared plus 2 x plus 1 equals 0 comma 2 x squared plus 3 x y minus 2 y squared plus 3 x plus y plus 1 equals 0  respectively then:

Maths-General

P1 = 1;
P2 = 1 half;
P3 = fraction numerator 1 over denominator square root of 7 end fraction;
>>> Therefore, we can say that P1>P2>P3.

General
Maths-

If θ is angle between pair of lines x squared minus 3 x y plus lambda y squared plus 3 x minus 5 y plus 2 equals 0, then cosec squared invisible function application theta equals

>>> lambda = 2.
>>> tantheta = 1 third
>>> cos e c squared theta = 10.

If θ is angle between pair of lines x squared minus 3 x y plus lambda y squared plus 3 x minus 5 y plus 2 equals 0, then cosec squared invisible function application theta equals

Maths-General

>>> lambda = 2.
>>> tantheta = 1 third
>>> cos e c squared theta = 10.

parallel

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