Question
is called benzoylacetonato. B is(Benzoylacetonato)beryllium will show:
- structuralisomerism
- geometricalisomerism
- opticalisomerism
- Noneofthese
The correct answer is: opticalisomerism
Benzoylacetonato is non-symmetrical didentate ligand and beryllium can only use sp3 orbitals (as it has no d-orbital). So Be forms tetrahedral complex with
Related Questions to study
Statement 1: adds to C=0 group irreversibly but ion adds reversibly
Statement 2: ion is much stronger nucleophile than ion
Statement 1: adds to C=0 group irreversibly but ion adds reversibly
Statement 2: ion is much stronger nucleophile than ion
Statement 1:Dehydration of gives as the minor product ad as the major product
Statement 2:can be dehydrated more readily than
Statement 1:Dehydration of gives as the minor product ad as the major product
Statement 2:can be dehydrated more readily than
Consider the following isomers of [Co(NH3)4Br2]+. The black sphere represents Co, gray spheres represent NH3 and unshade spheres represent Br.
Which structures are identical?
Consider the following isomers of [Co(NH3)4Br2]+. The black sphere represents Co, gray spheres represent NH3 and unshade spheres represent Br.
Which structures are identical?
Consider the following isomers of [Co(NH3)4Br2]+. The black sphere represents Co, gray spheres represent NH3 and unshade spheres represent Br.
Which of the following are trans-isomers?
Consider the following isomers of [Co(NH3)4Br2]+. The black sphere represents Co, gray spheres represent NH3 and unshade spheres represent Br.
Which of the following are trans-isomers?
Consider the following isomers of [Co(NH3)4Br2]+. The black sphere represents Co, gray spheres represent NH3 and unshade spheres represent Br.
Which of the following are cis-isomers?
Consider the following isomers of [Co(NH3)4Br2]+. The black sphere represents Co, gray spheres represent NH3 and unshade spheres represent Br.
Which of the following are cis-isomers?
Which of the following is not an organometallic compound?
Which of the following is not an organometallic compound?
In which of the following molecules are all the bonds not equal?
In which of the following molecules are all the bonds not equal?
The formal charge of the O-atoms in the ion is:
The formal charge of the O-atoms in the ion is:
The incentre of the triangle formed by the links x=0, y=0 and 3x+4y=12 is at
In order to answer this question, we used the formula for the coordinates of a triangle's in-center when the lengths of its sides a, b, and c are known, as well as the coordinates of its vertices. The incentre is (1,1).
The incentre of the triangle formed by the links x=0, y=0 and 3x+4y=12 is at
In order to answer this question, we used the formula for the coordinates of a triangle's in-center when the lengths of its sides a, b, and c are known, as well as the coordinates of its vertices. The incentre is (1,1).
Two vertices of a triangle are (3,-2) and (-2,3) and its orthocentre is (-6,1). Then its third vertex is
2x+y-4=0 and the x-y+7=0 are the equations that pass through the third vertex.
Two vertices of a triangle are (3,-2) and (-2,3) and its orthocentre is (-6,1). Then its third vertex is
2x+y-4=0 and the x-y+7=0 are the equations that pass through the third vertex.
If in triangle , circumcenter and orthocenter then the co-ordinates of mid-point of side opposite to is :
>>> The orthocenter, centroid and circumcenter of any triangle are collinear. And the centroid divides the distance from orthocenter to circumcenter in the ratio 2:1.
>>> Also, the centroid (G) divides the medians (AD) in the ratio 2:1.
>>> ∴D(h, k)=(1,)
If in triangle , circumcenter and orthocenter then the co-ordinates of mid-point of side opposite to is :
>>> The orthocenter, centroid and circumcenter of any triangle are collinear. And the centroid divides the distance from orthocenter to circumcenter in the ratio 2:1.
>>> Also, the centroid (G) divides the medians (AD) in the ratio 2:1.
>>> ∴D(h, k)=(1,)
A triangle ABC with vertices A(-1,0), B(-2,3/4)&C(-3,-7/6) has its orthocentre H. Then the orthocentre of triangle BCH will be
A triangle ABC with vertices A(-1,0), B(-2,3/4)&C(-3,-7/6) has its orthocentre H. Then the orthocentre of triangle BCH will be
ABC is an equilateral triangle such that the vertices B and C lie on two parallel lines at a distance 6 If A lies between the parallel lines at a distance 4 from one of them then the length of a side of the equilateral triangle is
>>> acosθ=6 ----(1)
>>> a(sin(30−θ))=4 ----(2)
>>> a =
ABC is an equilateral triangle such that the vertices B and C lie on two parallel lines at a distance 6 If A lies between the parallel lines at a distance 4 from one of them then the length of a side of the equilateral triangle is
>>> acosθ=6 ----(1)
>>> a(sin(30−θ))=4 ----(2)
>>> a =
If the point lies between the region corresponding to the acute angle between the lines x-3y=0 and x-6y=0 then
>>> L11 L22 <0
>>> (1+cos)2 -6sin -6sincos -3sin-3sincos+18sin2 < 0
If the point lies between the region corresponding to the acute angle between the lines x-3y=0 and x-6y=0 then
>>> L11 L22 <0
>>> (1+cos)2 -6sin -6sincos -3sin-3sincos+18sin2 < 0
If be any point on a line then the range of for which the point ' P ' lies between the parallel lines x+2y=1 and 2x+4y=15 is
((1+)+2() -1).() < 0
If be any point on a line then the range of for which the point ' P ' lies between the parallel lines x+2y=1 and 2x+4y=15 is
((1+)+2() -1).() < 0