Consider the following isomers of [Co(NH₃)₄Br₂]⁺. The black sphere represents Co, gray spheres represent NH₃ and unshade spheres represent Br.

Which of the following are trans-isomers?

Consider the following isomers of [Co(NH₃)₄Br₂]⁺. The black sphere represents Co, gray spheres represent NH₃ and unshade spheres represent Br.

Which of the following are cis-isomers?

Which of the following is not an organometallic compound?

In which of the following molecules are all the bonds not equal?

The formal charge of the O-atoms in the ion is:

The incentre of the triangle formed by the links x=0, y=0 and 3x+4y=12 is at

In order to answer this question, we used the formula for the coordinates of a triangle's in-center when the lengths of its sides a, b, and c are known, as well as the coordinates of its vertices. The incentre is (1,1).

Two vertices of a triangle are (3,-2) and (-2,3) and its orthocentre is (-6,1). Then its third vertex is

 2x+y-4=0 and the x-y+7=0 are the equations that pass through the third vertex.

If in triangle , circumcenter  and orthocenter  then the co-ordinates of mid-point of side opposite to  is :

>>> The orthocenter, centroid and circumcenter of any triangle are collinear. And the centroid divides the distance from orthocenter to circumcenter in the ratio $2:1$.
>>> Also, the centroid $(G)$ divides the medians $(AD)$ in the ratio $2:1.$
>>> ∴D(h, k)=(1,​)

A triangle ABC with vertices A(-1,0), B(-2,3/4)&C(-3,-7/6) has its orthocentre H. Then the orthocentre of triangle BCH will be

ABC is an equilateral triangle such that the vertices B and C lie on two parallel lines at a distance 6 If A lies between the parallel lines at a distance 4 from one of them then the length of a side of the equilateral triangle is

$>>>\; acos\theta =6$ ----(1)
$>>>\; a(sin(30-\theta ))=4$ ----(2)
>>> a = 

If the point  lies between the region corresponding to the acute angle between the lines x-3y=0 and x-6y=0 then

>>> L11  L22 <0
>>>   (1+cos)² -6sin -6sincos -3sin-3sincos+18sin² < 0

If  be any point on a line then the range of  for which the point ' P ' lies between the parallel lines x+2y=1 and 2x+4y=15 is

((1+)+2() -1).() < 0

is any point in the interior of the quadrilateral formed by the pair of lines  and the two lines 2x+y-2=0 and 4x+5y=20 then the possible number of positions of the points ' P ' is

If the point ,lies in the region corresponding to the acute angle between the lines 2y=x and 4y=x then - .....

u ≡ x - 2y = 0 and v ≡ x - 4y = 0
>>>    S(x, y) ≡ x² - 6xy + 8y² = 0
>>>     ( a - 2 )( a - 4 ) < 0

Consider A(0,1) and B(2,0) and P be a point on the line 4x+3y+9=0, co-ordinates of P such  is maximum is

 Hence the point is (, ).

Assertion (A): The lines represented by  and x+ y=2 do not form a triangle
Reason (R): The above three lines concur at (1,1)

Both Assertion and Reason are correct and the Reason is the correct explanation of Assertion.