Question
The maximum resultant of two forces is P and the minimum resultant is
, the two forces are at right angles, the resultant is
The correct answer is: ![square root of fraction numerator P to the power of 2 end exponent plus Q to the power of 2 end exponent over denominator 2 end fraction end root](data:image/png;base64,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)
![](https://mycourses.turito.com/tokenpluginfile.php/c161933dbfaab094c54655ab71e9b8f0/1/question/answer/858159/1/3843808/Picture3462.x-wmf)
Let the 2 forces be F1 and F2.
Maximum resultant = P = F1 + F2
Minimum resultant = Q = F1 – F2
F1 = [P + Q] / 2 and F2 = [P – Q] / 2
![straight R equals square root of straight F subscript 1 superscript 2 plus straight F subscript 2 superscript 2 end root equals square root of open square brackets straight P squared plus straight Q squared close square brackets end root divided by 2](data:image/png;base64,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)
Related Questions to study
The resultant of two forces
and
is of magnitude P. If the force
is doubled,
remaining unaltered, the new resultant will be
The resultant of two forces
and
is of magnitude P. If the force
is doubled,
remaining unaltered, the new resultant will be
The resultant of two forces 3P and 2P is R, if the first force is doubled, the resultant is also doubled. The angle between the forces is
In this question, we have to make two equations of Resultant as per given instruction and solve the equations and find the angle. Remember the formula of Resultant is R =
The resultant of two forces 3P and 2P is R, if the first force is doubled, the resultant is also doubled. The angle between the forces is
In this question, we have to make two equations of Resultant as per given instruction and solve the equations and find the angle. Remember the formula of Resultant is R =
If the gradient of the tangent at any point (x, y) of a curve which passes through the point
is
then equation of the curve is
If the gradient of the tangent at any point (x, y) of a curve which passes through the point
is
then equation of the curve is
If
, then
is
In this question, we have given ycosx + xcosy =π . Differentiate this equation with request to x and do separate second derivate and find the value of it.
If
, then
is
In this question, we have given ycosx + xcosy =π . Differentiate this equation with request to x and do separate second derivate and find the value of it.
The solution of the differential equation
is equal to
In this question, you have to find the solution of differential equation x4 + x3 y + cosec (xy) = 0. Use variable separable method to find the solution.
The solution of the differential equation
is equal to
In this question, you have to find the solution of differential equation x4 + x3 y + cosec (xy) = 0. Use variable separable method to find the solution.
A continuously differentiable function
satisfying
is
A continuously differentiable function
satisfying
is
The slope of the tangent at
to a curve passing through
is given by
, then the equation of the curve is
The slope of the tangent at
to a curve passing through
is given by
, then the equation of the curve is
A solution of the differential equation
is
A solution of the differential equation
is
If integrating factor of
is
then P is equal to
If integrating factor of
is
then P is equal to
The solution of the given differential equation
is
The solution of the given differential equation
is
The general solution of
is
The general solution of
is
The solution of the differential equation
is
The solution of the differential equation
is
The solution of the differential equation
is
The solution of the differential equation
is
The solution of the differential equation
is
A differential equation is an equation which contains one or more terms and the derivatives of one variable (i.e., dependent variable) with respect to the other variable (i.e., independent variable) dy/dx = f(x)
The solution of the differential equation
is
A differential equation is an equation which contains one or more terms and the derivatives of one variable (i.e., dependent variable) with respect to the other variable (i.e., independent variable) dy/dx = f(x)